2(2

^{n-1}) = 2

^{n}but I don't see how this is.

It seems to me that 2(2

^{n-1}) = 4

^{n-1}

What is the rule at work here?

I'm learning discrete math, but having a problem with an algebraic simplification, so I think I'm posting this in the right place.

2(2^{n-1}) = 2^{n} but I don't see how this is.

It seems to me that 2(2^{n-1}) = 4^{n-1}

What is the rule at work here?

2(2

It seems to me that 2(2

What is the rule at work here?

- little_dragon
**Posts:**215**Joined:**Mon Dec 08, 2008 5:18 pm-
**Contact:**

mathstuff wrote:2(2^{n-1}) = 2^{n}but I don't see how this is.

It seems to me that 2(2^{n-1}) = 4^{n-1}

What is the rule at work here?

do the regular exponent stuff: http://www.purplemath.com/modules/exponent.htm

it's 2(2

it's (2