I'm not seeing a "4a/4a", and the "-c/a" appears to be unchanged between line 4 and line 5...?4. x2 + bx/a + b2/4a2 = -c/a + b2/4a2
5. (x + b/2a)2 = -c/a + b2/4a2
This is where I'm stuck. How do you get 4a/4a from the a in -c/a?
The simplest common denominator of the terms on the right hand side is 4a2. To add rational expressions, in this case you want to do this:This is where I'm stuck. How do you get 4a/4a from the a in -c/a? Like I said in my original post, a variable without a coefficient has an implied coefficient of 1. So really -c/a is -1c/1a. How does 4a come from 1a? 1 only has itself as a multiple, where is the 4 coming from?