log

_{3}(3square root x /81)

I get:

1/3log

_{3}x-4

Did I do this correctly?

I am checking my answer to expand my expression:

log_{3}(3square root x /81)

I get:

1/3log_{3} x-4

Did I do this correctly?

log

I get:

1/3log

Did I do this correctly?

- stapel_eliz
**Posts:**1743**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

Expanding log_{3}[3SQRT(x/81)]

here are 5 BIG HINTS:

1) Product Property of Logarithms

2) A root is an exponent (find out what SQRT means!)

3) Power Property of Logarithms

4) Quotient Property of Logarithms

5) log_{a}a = 1

Now just do it!

...

ok, answer is (1/2)log_{3}x - 2

here are 5 BIG HINTS:

1) Product Property of Logarithms

2) A root is an exponent (find out what SQRT means!)

3) Power Property of Logarithms

4) Quotient Property of Logarithms

5) log

Now just do it!

...

ok, answer is (1/2)log