=
=
=
=
=
The revision handbook gives the following as options:
1.
2.
3.
4.
5. none of the above.
I'm second-guessing my calculation. Please could someone review my method?
Simplification of complex fractions.
Simplification of complex fractions.
This is my attempt at simplification below:
(8^{3x})}{(2^{3x})(4^{x+2})})
=(2^{2x})(2^4)})
=(2^{2x})(2^4)})
=(2^{-3x})(2^{-2x})(2^{-4}))
=(2^{-4}))
=(\frac{1}{16}))
The revision handbook gives the following as options:
1.(16))
2.
3.
4.
5. none of the above.
I'm second-guessing my calculation. Please could someone review my method?
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=
=
=
=
The revision handbook gives the following as options:
1.
2.
3.
4.
5. none of the above.
I'm second-guessing my calculation. Please could someone review my method?
Re: Simplification of complex fractions.
Ian wrote:This is my attempt at simplification below:
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=
=
=
=
The revision handbook gives the following as options:
1.
2.
3.
4.
5. none of the above.
I'm second-guessing my calculation. Please could someone review my method?
yrs is the same as #2
Re: Simplification of complex fractions.
Voilà! I completely (ashamedly) missed that. Thanks.