I am learning the system of linear equations and my teacher game me some elimination problems. I'm really stumped because its not what I'm used to
. If you can solve it please explain and show your work. Thank you
Topic should be placed in Beginning Algebra subforum.
The system of equation seems to use variables x and y for the "unknown" variables. a
is another variable but may be taken to act as a constant. The system is suitable to easily eliminate the terms of y to find x. As the system is in its current form, just subtract the second equation from the first equation. That would be like this:
3ax +0 =-6 (actually, I multiplied by -1 and then added it).
Now if you want to eliminate x to find y, some multiplying of both equations is necessary.
You want to multiply both equations each by its own chosen factor to have the same term of x. Simplest result is 2*5=10.
2*(5ax+3y=5) = 10ax+6y=10
5*(2ax+3y=11) = 10ax+15y=55
Now using the system in that multiplied form, subtract the first from the second:
The solution or answer then for the original system is x=-2a and y=44/9.