## plz help me simplify F=A'.B'(A.B+B')

Simplificatation, evaluation, linear equations, linear graphs, linear inequalities, basic word problems, etc.
ALI
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Joined: Fri Jun 14, 2013 6:51 am
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### plz help me simplify F=A'.B'(A.B+B')

As I am new in this plz can some one help me to simplify this expression ,i try but i am not sure is it corect or wrong.
expression is
F=A'.B'(A.B+B')

F=A'.B'(AB+B')
F=A'.B'(A+B+B') BY USING DEMORGAN LAW
F=A'.B'(A+(B+B')) By rearranging above expression
F=A'.B'(A+1) BY USING RULE#11
F=A'.B' BY USING RULE #5
F=(A+B)'

maggiemagnet
Posts: 358
Joined: Mon Dec 08, 2008 12:32 am
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### Re: plz help me simplify F=A'.B'(A.B+B')

As I am new in this plz can some one help me to simplify this expression...
F=A'.B'(A.B+B')
Does the "prime" notation (the apostrophe after the letters) mean "not", or "complement", or something else? What does "plus" mean? What does the "dot" mean? Is there any "priority" so, say, the "dot" binds more tightly than does the "plus" -- so A.B+B' means (A.B)+B'? Thanks!

ALI
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Joined: Fri Jun 14, 2013 6:51 am
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### Re: plz help me simplify F=A'.B'(A.B+B')

Dear this ' is compliment dot means AND gate and plus means OR gate

maggiemagnet
Posts: 358
Joined: Mon Dec 08, 2008 12:32 am
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### Re: plz help me simplify F=A'.B'(A.B+B')

Dear this ' is compliment dot means AND gate and plus means OR gate
From "gate" I'm going to guess that you're doing circuits, etc, like they talk about here that "complement" means logical "not". I'm assuming that the "math" stuff follows the usual order of operations rules so you have this:

(not-A and not-B) and ([A and B] or not-B)

Are there any rules here that you're not allowed to use? Thanks!