**very**simple...I need to solve for "y". But I don't understand how to "flip" the problem into fraction form to solve. Any guidance is appreciated!!

4y=3

Help! I know this is **very** simple...I need to solve for "y". But I don't understand how to "flip" the problem into fraction form to solve. Any guidance is appreciated!!

4y=3

4y=3

- maggiemagnet
**Posts:**354**Joined:**Mon Dec 08, 2008 12:32 am-
**Contact:**

mrscobb wrote:I need to solve for "y". But I don't understand how to "flip" the problem into fraction form to solve. Any guidance is appreciated!

You can learn how to do this here!

The equation: ** 4y=3 **

The frist thing is to make sure that only**'y'** or the **'unknown(s)'** remain in one side and **the number types(... -2,-1, 0, 1, 2, ...) **the other side.

The second thing is to make sure that what is done to one side of the equation is equally done to the other.

**4y = 3**

In order to make 'y' remains on one side, we find a way to eliminate '4' from 'y'

Then, dividing**4y** by **4** will eliminate **4**, given **4/4 = 1** . So **1y = y**

Remember, what we did to left side of equation**unknown or 'y' **must be done to the right side of the equation that has **3**. That is, dividing the right side of the equation by **4** as well. Given **3/4**

**4/4y = 3/4** , which gives **1y = 3/4**. Since **1y = y , y = 3/4**

The frist thing is to make sure that only

The second thing is to make sure that what is done to one side of the equation is equally done to the other.

In order to make 'y' remains on one side, we find a way to eliminate '4' from 'y'

Then, dividing

Remember, what we did to left side of equation