[ 2 1 ] * A = [ 3 0 ]

[ 0 3 ] [-3 6 ]

To solve for A, would you divide the right matrix by the one on the left? If so, I come up with the following:

[ 3/2 3 ]

[-3/2+6/0 -1 ]

But what do I do with that 6/0?

I have a question about matrix multiplication; well, actually, matrix division. I am assuming that matrices are divided the same as they are multiplied; that is, row by column. Specifically, the problem I am referring to:

To solve for A, would you divide the right matrix by the one on the left? If so, I come up with the following:

But what do I do with that 6/0?

[ 2 1 ] * A = [ 3 0 ]

[ 0 3 ] [-3 6 ]

To solve for A, would you divide the right matrix by the one on the left? If so, I come up with the following:

[ 3/2 3 ]

[-3/2+6/0 -1 ]

But what do I do with that 6/0?

- Martingale
**Posts:**344**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
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lawrence wrote:I have a question about matrix multiplication; well, actually, matrix division. I am assuming that matrices are divided the same as they are multiplied; that is, row by column. Specifically, the problem I am referring to:[ 2 1 ] * A = [ 3 0 ]

[ 0 3 ] [-3 6 ]

To solve for A, would you divide the right matrix by the one on the left? If so, I come up with the following:[ 3/2 3 ]

[-3/2+6/0 -1 ]

But what do I do with that 6/0?

you need to find the inverse matrix for

and multiply that to both sides

- stapel_eliz
**Posts:**1686**Joined:**Mon Dec 08, 2008 4:22 pm-
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lawrence wrote:I have a question about matrix multiplication; well, actually, matrix division. I am assuming that matrices are divided the same as they are multiplied...

No; division is not defined for matrices. As the previous reply suggests, you have to use a different process. (I'm guessing you're self-studying or thinking ahead of your class syllabus...?)

With numbers, dividing by a value was the same as multiplying by the "multiplicative inverse", being the reciprocal of the intended divisor. For instance, 10 divided by 2 is the same as 10 times 1/2.

While matrices cannot be divided, they can (sometimes) have multiplicative inverses. To learn about this topic and the process for finding an inverse, try

Thank you both!