- Mon Mar 30, 2015 5:23 pm
- Forum: Beginning Algebra
- Topic: Linear independence & linear dependence
- Replies:
**1** - Views:
**47**

Suppose that vectors v1,v2,v3 are linearly independent. (i) Prove that v1-v2, v2-v3 and v3-v1 are linearly dependent. (ii) Prove that v1+v2, v2+v3 and v3+v1 are linearly dependent. I need you guys to help me solve this question.... To learn how to show linear dependence try here . Then set things u...

- Fri Jan 16, 2015 3:18 pm
- Forum: Trigonometry
- Topic: angles of a oblique triange
- Replies:
**4** - Views:
**447**

I think the usual way of saying it would like something like this:

"ABC is a triangle. Opposite the vertices A, B, and C are the sides a, b, and c, respectively. The lengths of the sides are: a = 88, b = 72, and c = 110. Find the measures of the angles at A and at C."

"ABC is a triangle. Opposite the vertices A, B, and C are the sides a, b, and c, respectively. The lengths of the sides are: a = 88, b = 72, and c = 110. Find the measures of the angles at A and at C."

- Fri Jan 16, 2015 3:14 pm
- Forum: Beginning Algebra
- Topic: Domain and Range of a relation
- Replies:
**5** - Views:
**724**

Then which is the independent variable and which is the dependent variable? The domain and range depend on this information! Thanks!

- Thu Jan 15, 2015 12:27 pm
- Forum: Intermediate Algebra
- Topic: Pondering Base and Exponent, Both NEGATIVE
- Replies:
**3** - Views:
**475**

I wrote up a problem for myself to test the behavior of a negative exponent with a negative base.... y\, =\, \dfrac{(-5)^{-x}}{34} Before I proceed, I will do a mini-proof of the numerator. (-5)^{-x}\, =\, \dfrac{x}{(-5)^1}\, =\, \dfrac{x}{(-5)} Is this math correct?...

- Sat Nov 22, 2014 2:03 pm
- Forum: Statistics
- Topic: I need help to solve this question
- Replies:
**1** - Views:
**700**

The following table represents the absent days of a sample of students in the statistics course Absent days 0 1 2 3 4 Number of students 10 5 8 Y 3 Determine the value of Y if the median of the absent days is 1.5 day. The " median " is the middle value in the list. So write out the list: ...

- Mon Nov 10, 2014 6:29 pm
- Forum: Statistics
- Topic: Expected Value of Probability Density Function
- Replies:
**1** - Views:
**499**

I am trying to find the Expected Value of the following Probability Density Functions (where E is Euler's number) for the x values shown below. For some reason I get very different values from my calculations of the expected value when applying the discrete and continuous method of calculating expe...

- Sun Nov 02, 2014 12:18 am
- Forum: Intermediate Algebra
- Topic: beginner f(x) domain
- Replies:
**1** - Views:
**536**

I have f(x)= x^2 +5x +6 find the domain , all possible values of x The "domain" is all values of x that will work in the function. so f(x) = x^2 + 5x +6 factors out to (x+3) (x+2) Imy anser is x is all rational numbers except -3 or -2 Why is your function not allowed to equal zero? Dividi...

- Thu Oct 23, 2014 11:15 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: degree of quotient of polynomials
- Replies:
**1** - Views:
**592**

1) Is it correct to assert that the degree of the quotient is always equal to the degree of the numerator minus the degree of the denominator? I've never before heard of the "degree" of a rational function but, yes, I think it would be computed the way you've described. On the other hand,...

- Mon Sep 15, 2014 10:20 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Creating a function given its vertex
- Replies:
**8** - Views:
**1560**

PsylentKnight wrote:My professor ended up working this one out in class...

...a = -16/84 = -4/21

Okay, so I made a typo somewhere. I used the same method but got a = -4/13. Oops!

- Fri Sep 12, 2014 4:00 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Creating a function given its vertex
- Replies:
**8** - Views:
**1560**

How about if we set a = 1 and hope we can find something that works? a= 1 = (4x+1)/(x-3)^2 (x - 3)^2 = 4x + 1 x^2 - 6x + 9 = 4x + 1 x^2 - 10x + 8 = 0 But if you do the Quadratic Formula you get 2 solutions and you have to get only 1 because of what tangents do. So maybe try timesing it out: a(x^2 - ...