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by maggiemagnet
Mon Jan 04, 2016 12:44 am
Forum: Intermediate Algebra
Topic: Need help finding f(x)
Replies: 1
Views: 187

Re: Need help finding f(x)

how can I find: ((f(x+h) - f(x))/h If f(x) = 1/(square root x) Can someone help me? You can do this like they show here . Work it step by step like they show. What is f(x) for this? What is f(x + h), after simplifying? What is the subtraction, after simplifying? Please show all your work for each p...
by maggiemagnet
Mon Nov 30, 2015 12:20 pm
Forum: Calculus
Topic: Is f(x)=sqrt(x^2) differentiable at x=0?
Replies: 2
Views: 191

Re: Is f(x)=sqrt(x^2) differentiable at x=0?

I've seen the absolute function described as a composite function which is clearly not differentiable at x=0. However I've also seen it described as f(x)=sqrt(x^2) which I have been led to believe is differentiable at x=0. My understanding is that it's not a sharp point, it's an infinitely tiny cur...
by maggiemagnet
Fri Nov 13, 2015 9:29 pm
Forum: Trigonometry
Topic: Finding all the solutions of the equation
Replies: 4
Views: 208

Re: Finding all the solutions of the equation

Sorry, I honestly have no idea, why would you do that? :confused: I think the poster was trying to point out that your equation is a quadratic type so you can apply the same formulas. Here you can plug into the quadratic formula (at the link in that post) to get simple solve-able trig equations. So...
by maggiemagnet
Fri Nov 06, 2015 7:28 pm
Forum: Calculus
Topic: Integration using algebraic substitution
Replies: 4
Views: 338

Re: Integration using algebraic substitution

bazbeatz wrote:Well then i get...

=1/30 (5(x-2)^6 + 12(x-2)^5)+C

which is still different to the answer provided unless i am missing something

What happens when you take the common factor of (x - 2)5 out front?

(1/30) [ 5(x - 2)5 (x - 2) + 12(x - 2)5 ] = (1/30) [ (x - 2)5 (5(x - 2) + 12) ] = ??

:clap:
by maggiemagnet
Fri Nov 06, 2015 2:09 am
Forum: Advanced Algebra ("pre-calculus")
Topic: Equation for a square
Replies: 1
Views: 315

Re: Equation for a square

But that "astroid" is a curve. A square isn't curved, so the same kind of equation probably won't work. The only thing I could find is stuff like here. Good luck!
:clap:
by maggiemagnet
Fri Nov 06, 2015 2:07 am
Forum: Calculus
Topic: Integration using algebraic substitution
Replies: 4
Views: 338

Re: Integration using algebraic substitution

What do you get if you do the back-subbing to get back to "x" (instead of "u")?
:clap:
by maggiemagnet
Thu Nov 05, 2015 12:51 am
Forum: Uncategorized
Topic: Tick tock!
Replies: 2
Views: 219

Re: Tick tock!

In a 12 hours period, starting exactly at 00.00, how often does: 1: the minute hand overlap the hour hand The minute hand doesn't cross over the hour hand from midnight (00:00:01) to 1am because the minute hand is always "ahead" of the hour hand. The minute hand crosses over once an hour ...
by maggiemagnet
Tue Oct 20, 2015 11:58 pm
Forum: Intermediate Algebra
Topic: inverse f(inverse g(x)) = inverse g(inverse f(x))
Replies: 2
Views: 303

Re: inverse f(inverse g(x)) = inverse g(inverse f(x))

f(x) = 24x-15 and g(x)=2x-d where d is an unknown value, it is known that inverse f(inverse g(x)) = inverse g(inverse f(x)) I have to first of all find the value of d, and secondly find; inverse f(inverse g(20)) We have been using mathCAD to solve similar but I really want to learn how to solve thi...
by maggiemagnet
Tue Oct 20, 2015 11:39 pm
Forum: Discrete Math
Topic: Prove or disprove: If f:X->Y and g:Y->X are functions such that g o f = I_x and f o g = I_y, then
Replies: 1
Views: 549

Re: Prove or disprove: If f:X->Y and g:Y->X are functions such that g o f = I_x and f o g = I_y, then

Pharlap7404 wrote:Prove or give a counterexample:
If f:X->Y and g:Y->X are functions such that g o f = Ix and f o g = Iy
then f and g are both one-to-one and onto and g = f-1

What is "Ix"? "Iy"? When you write back, please give your thoughts and steps so far. Thanks!
:clap:

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