Sleepy Ash wrote:...what makes a problem like this

\sqrt{b^1^8}=\left| b^9 \right|

End up with an absolute value.

I don't understand how they got that 1^8 = 9?? (b^1)^8 = (b)^8 = b^8, not b^9.

- Mon Aug 17, 2015 2:34 pm
- Forum: Intermediate Algebra
- Topic: Roots of exponential expressions
- Replies:
**3** - Views:
**87**

Sleepy Ash wrote:...what makes a problem like this

\sqrt{b^1^8}=\left| b^9 \right|

End up with an absolute value.

I don't understand how they got that 1^8 = 9?? (b^1)^8 = (b)^8 = b^8, not b^9.

- Sun Jul 12, 2015 11:00 am
- Forum: Trigonometry
- Topic: Reciprocal trigonometric ratios
- Replies:
**5** - Views:
**91**

i did the inverse function of tan (3.2404) and got 72.8.... my answer sheet says its supposed to be 17, what did i do wrong?what am i supposed to do? It's cotangent, not tangent. Do the relationship between cotangent and tangent to convert the equation to what your calculator can do: tan(x)=1/cot(x...

- Tue Jun 09, 2015 2:37 am
- Forum: Forum Rules & Guides
- Topic: Was my post reported and if so why?
- Replies:
**2** - Views:
**536**

The only "counting" problem I'm seeing is from October of last year: viewtopic.php?f=15&t=4039

I think they don't want way old threads bumped.

I think they don't want way old threads bumped.

- Thu Jun 04, 2015 8:13 pm
- Forum: Calculus
- Topic: I have this optimization problem that Im having trouble on
- Replies:
**1** - Views:
**528**

This is the questions: Person A and B sells item x for $200 a month, and they sell 150 objects per month Person B says that for every $15 rebate they give, they will get 50 more objects sold. Person A disagrees. Who is correct? What is the amount of rebate that should be given? What price will maxi...

- Fri May 15, 2015 8:41 pm
- Forum: Intermediate Algebra
- Topic: Simplify the following expression...how?
- Replies:
**3** - Views:
**302**

Simplify the following expression. Write the answer with positive exponents and assume the variable represents a nonreal number. - 1/9 w^-8 times (-36w^-3) I don't see why you're supposed to "assume the variable represents a [complex or imaginary] number"...? Before the "times",...

- Fri May 15, 2015 7:02 pm
- Forum: Intermediate Algebra
- Topic: linear programming question - Problem with Constrain
- Replies:
**2** - Views:
**272**

I'm sorry but I don't understand what you're trying to do. What is the EXACT text of the exercise? What are the EXACT parameters? How are the constraints defined? What do you mean by "submitting as two scores"?

Thanks.

Thanks.

- Thu Apr 30, 2015 4:03 pm
- Forum: Calculus
- Topic: integral cos (Pi * x)
- Replies:
**1** - Views:
**360**

can anyone help me with the intigral of (pi * x) Since \,\pi\, is just a number, the integral of \,\pi\,x\, works just like the integral of any other product of \,x\, and a number: \int\, ax\, dx\, =\, a\, \left(\dfrac{x^2}{2}\right) In your subject line, you also ask about the integral of ...

- Sat Feb 14, 2015 3:38 pm
- Forum: Calculus
- Topic: Given z=x²+3xy-2y²
- Replies:
**2** - Views:
**586**

Given z=x²+3xy-2y² Estimate the change in z when x changes from 2 to 2,5 and y changes from 3 to 2,5 What method are you supposed to use to do the estimation? Did they give you any formulas, like partial-dz = (partial-dz/partial-dy)dy + (partial-dz/partial-dx)dx? Or maybe something like is in this ...

- Sat Jan 24, 2015 4:03 am
- Forum: Calculus
- Topic: Help needed to evaluate limits
- Replies:
**5** - Views:
**1194**

Do you know how to read? Yes, I do. Do you? I showed you all the steps and explained that the result means that the limit of negative 2 times negative numbers, as those numbers get really, really far negative, is positive infinity, so the limit is "+infty". Why do you think showing your w...

- Fri Jan 23, 2015 8:07 pm
- Forum: Calculus
- Topic: Help needed to evaluate limits
- Replies:
**5** - Views:
**1194**

Anonmeans, thank you, but can you please answer my question? I gave you all the steps. I showed you the limit expression is -2x. I pointed out that x < 0. Algebra says x < 0 means -2x > 0 so, when you take the limit, the value has to be positive. What part do you still need answered for you? :confu...