- Wed Jan 28, 2009 6:34 pm
- Forum: Beginning Algebra
- Topic: This is quite graphic...
- Replies:
**2** - Views:
**2304**

Thanks for the reply Elizabeth, I went over the examples about 10 times last night and finally figured it out. Everything you're saying I know. I guess I didn't have the confidence in my work that I should have. The answer to the problem is indeed -13 and 23. if the tent is 10' wide then coming from...

- Wed Jan 28, 2009 1:51 am
- Forum: Beginning Algebra
- Topic: This is quite graphic...
- Replies:
**2** - Views:
**2304**

:wink: I don't know why I'm having so much trouble with this, obviously I'm missing something. SO here goes. I have a tent that's going to be staked out on a polar ice cap and as you can imagine it's cold and windy out here. My partner is the meticulous type and wants to know how high the tent is so...

- Sun Jan 25, 2009 11:12 pm
- Forum: Beginning Algebra
- Topic: Graphing |7 - 3x| - 10 = 4
- Replies:
**4** - Views:
**5026**

Hmmm, a question just came up. You wrote; Instead, consider the two cases. If -3x + 7 > 0, then 7/3 > x (or, as I prefer, x < 7/3). So, assuming x to be in this range, we then get: . . . . .|7 - 3x| - 10 = 4 . . . . .(7 - 3x) - 10 = 4 Here the sign didn't change. Is that because we are assuming that...

- Sun Jan 25, 2009 10:42 pm
- Forum: Beginning Algebra
- Topic: Graphing |7 - 3x| - 10 = 4
- Replies:
**4** - Views:
**5026**

I see that now. I got the idea after doing the graph and doing a little more reading but your explanation helps me even more.

Thanks Elizabeth!

Thanks Elizabeth!

- Sun Jan 25, 2009 10:18 pm
- Forum: Beginning Algebra
- Topic: Graphing |7 - 3x| - 10 = 4
- Replies:
**4** - Views:
**5026**

I have a question on negative numbers in absolute value equations. For instance: |7-3x|-10=4 |-3x+7|-10=4 -3x+7=14 -3x = 7 x = - \frac 73 This is fine for me. I'm assuming that the result is a negative based on the division by -3. The book says that's correct. The other solution is what's giving me ...

- Sat Jan 24, 2009 3:55 pm
- Forum: Pre-Algebra
- Topic: -1^2: is this equal to -1 or to 1?
- Replies:
**7** - Views:
**7023**

Thanks for your reply.

I think I see it now. The substitution is -1 not . obviously the square is then and not .

There are two solutions when taking the square root of a positive number? Really? What's the other solution?

Thanks again!

Daniel

I think I see it now. The substitution is -1 not . obviously the square is then and not .

There are two solutions when taking the square root of a positive number? Really? What's the other solution?

Thanks again!

Daniel

- Sat Jan 24, 2009 2:03 pm
- Forum: Pre-Algebra
- Topic: -1^2: is this equal to -1 or to 1?
- Replies:
**7** - Views:
**7023**

Ok, I did a little reading on this and thought I had the concept down but apparently I'm missing something. The big question is does -1^2 equal -1 or 1? It's -1 from the explanation I read which makes perfect sense to me, if -1^2 = (-1^2) = -(1)(1) then -1^2 = -1 . If, (-...

- Sat Jan 24, 2009 1:15 pm
- Forum: Arithmetic
- Topic: Simplify: I get y = (10-2x)/5 but book says y = (1/5)(10-2x)
- Replies:
**4** - Views:
**6400**

Hey Little Dragon, I know, isn't that annoying? In Linear equations they want the answer to look like y=\frac15(10-2x) but now that we're graphing, the very next chapter, they want the answer to look like y = 2-.4x . And they didn't say they wanted it in the simpler form. I'm still counting ...

- Fri Jan 23, 2009 10:58 pm
- Forum: Arithmetic
- Topic: Simplify: I get y = (10-2x)/5 but book says y = (1/5)(10-2x)
- Replies:
**4** - Views:
**6400**

"Ah, now I see!" said the blind man. :wink: y=\frac15(10-2x) is what the book says is correct. I say this is as correct y=\frac{10-2x}{5} but isn't this: y=2-.4x, simpler yet? I like the decimal form of the answer much better as I'm very used to converting fractions to decimals in ...

- Fri Jan 23, 2009 10:37 pm
- Forum: Beginning Algebra
- Topic: Transformation trouble: 3x + 3/2(2x - 1) = 2
- Replies:
**2** - Views:
**3570**

Elizabeth,

Thanks for the reply and apologies for not getting back sooner.

I figured out what I did wrong in the above equation. I didn't distribute properly. The answer is .58 or 7 divided by 12.

Thanks again!

Thanks for the reply and apologies for not getting back sooner.

I figured out what I did wrong in the above equation. I didn't distribute properly. The answer is .58 or 7 divided by 12.

Thanks again!