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by diaste
Wed Jan 28, 2009 6:34 pm
Forum: Beginning Algebra
Topic: This is quite graphic...
Replies: 2
Views: 1804

Re: This is quite graphic...

Thanks for the reply Elizabeth, I went over the examples about 10 times last night and finally figured it out. Everything you're saying I know. I guess I didn't have the confidence in my work that I should have. The answer to the problem is indeed -13 and 23. if the tent is 10' wide then coming from...
by diaste
Wed Jan 28, 2009 1:51 am
Forum: Beginning Algebra
Topic: This is quite graphic...
Replies: 2
Views: 1804

This is quite graphic...

:wink: I don't know why I'm having so much trouble with this, obviously I'm missing something. SO here goes. I have a tent that's going to be staked out on a polar ice cap and as you can imagine it's cold and windy out here. My partner is the meticulous type and wants to know how high the tent is so...
by diaste
Sun Jan 25, 2009 11:12 pm
Forum: Beginning Algebra
Topic: Graphing |7 - 3x| - 10 = 4
Replies: 4
Views: 4217

Re: Graphing |7 - 3x| - 10 = 4

Hmmm, a question just came up. You wrote; Instead, consider the two cases. If -3x + 7 > 0, then 7/3 > x (or, as I prefer, x < 7/3). So, assuming x to be in this range, we then get: . . . . .|7 - 3x| - 10 = 4 . . . . .(7 - 3x) - 10 = 4 Here the sign didn't change. Is that because we are assuming that...
by diaste
Sun Jan 25, 2009 10:42 pm
Forum: Beginning Algebra
Topic: Graphing |7 - 3x| - 10 = 4
Replies: 4
Views: 4217

Re: Graphing |7 - 3x| - 10 = 4

I see that now. I got the idea after doing the graph and doing a little more reading but your explanation helps me even more.

Thanks Elizabeth! :)
by diaste
Sun Jan 25, 2009 10:18 pm
Forum: Beginning Algebra
Topic: Graphing |7 - 3x| - 10 = 4
Replies: 4
Views: 4217

Graphing |7 - 3x| - 10 = 4

I have a question on negative numbers in absolute value equations. For instance: |7-3x|-10=4 |-3x+7|-10=4 -3x+7=14 -3x = 7 x = - \frac 73 This is fine for me. I'm assuming that the result is a negative based on the division by -3. The book says that's correct. The other solution is what's giving me ...
by diaste
Sat Jan 24, 2009 3:55 pm
Forum: Pre-Algebra
Topic: -1^2: is this equal to -1 or to 1?
Replies: 7
Views: 6238

Re: -1^2

Thanks for your reply.
I think I see it now. The substitution is -1 not . obviously the square is then and not .

There are two solutions when taking the square root of a positive number? Really? What's the other solution?

Thanks again!

Daniel
by diaste
Sat Jan 24, 2009 2:03 pm
Forum: Pre-Algebra
Topic: -1^2: is this equal to -1 or to 1?
Replies: 7
Views: 6238

-1^2: is this equal to -1 or to 1?

Ok, I did a little reading on this and thought I had the concept down but apparently I'm missing something. The big question is does -1^2 equal -1 or 1? It's -1 from the explanation I read which makes perfect sense to me, if -1^2 = (-1^2) = -(1)(1) then -1^2 = -1 . If, (-...
by diaste
Sat Jan 24, 2009 1:15 pm
Forum: Arithmetic
Topic: Simplify: I get y = (10-2x)/5 but book says y = (1/5)(10-2x)
Replies: 4
Views: 5388

Re: Simplify: I get y = (10-2x)/5 but book says y = (1/5)(10-2x)

Hey Little Dragon, I know, isn't that annoying? In Linear equations they want the answer to look like y=\frac15(10-2x) but now that we're graphing, the very next chapter, they want the answer to look like y = 2-.4x . And they didn't say they wanted it in the simpler form. I'm still counting ...
by diaste
Fri Jan 23, 2009 10:58 pm
Forum: Arithmetic
Topic: Simplify: I get y = (10-2x)/5 but book says y = (1/5)(10-2x)
Replies: 4
Views: 5388

Re: Simplify

"Ah, now I see!" said the blind man. :wink: y=\frac15(10-2x) is what the book says is correct. I say this is as correct y=\frac{10-2x}{5} but isn't this: y=2-.4x, simpler yet? I like the decimal form of the answer much better as I'm very used to converting fractions to decimals in ...
by diaste
Fri Jan 23, 2009 10:37 pm
Forum: Beginning Algebra
Topic: Transformation trouble: 3x + 3/2(2x - 1) = 2
Replies: 2
Views: 3110

Re: Transformation trouble: 3x + 3/2(2x - 1) = 2

Elizabeth,
Thanks for the reply and apologies for not getting back sooner.
I figured out what I did wrong in the above equation. I didn't distribute properly. The answer is .58 or 7 divided by 12.
Thanks again!

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