- Sat Jan 12, 2013 9:54 am
- Forum: Intermediate Algebra
- Topic: Factoring trinomials: 2a^2 + 3a + 1
- Replies:
**3** - Views:
**11500**

Those are REALLY good suggestions, the last one is actually the fastest way to solve the problem. But remember that if you ever get stuck, there is a guaranteed solution to any quadratic equation using the Quadratic Formula (and if there isn't, it means the equation is unsolvable, or at least has no...

- Sat Jan 12, 2013 9:39 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: I need help developing an equation
- Replies:
**4** - Views:
**5358**

I guess OP isn't coming back, so the answers are

a_{n}= 5(3n-1)

and

S_{n}=(10/2)[(10)+(145)]= $775.

a

and

S

- Fri Jan 11, 2013 2:08 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Linear equation deduction enigma
- Replies:
**2** - Views:
**6117**

No one's gonna look at this, and I don't know if this helps, but from a Production standpoint in EconA: Skilled Labor produces y more effectively Unskilled Labor produces x more effectively EconA producing soly x or y is double the output of that of that in EconB. Graph all 3 lines on the same plane...

- Fri Jan 11, 2013 12:51 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Expand Expression
- Replies:
**2** - Views:
**2419**

Expanding log_{3}[3SQRT(x/81)]

here are 5 BIG HINTS:

1) Product Property of Logarithms

2) A root is an exponent (find out what SQRT means!)

3) Power Property of Logarithms

4) Quotient Property of Logarithms

5) log_{a}a = 1

Now just do it!

...

ok, answer is (1/2)log_{3}x - 2

here are 5 BIG HINTS:

1) Product Property of Logarithms

2) A root is an exponent (find out what SQRT means!)

3) Power Property of Logarithms

4) Quotient Property of Logarithms

5) log

Now just do it!

...

ok, answer is (1/2)log

- Fri Jan 11, 2013 12:36 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: I need help developing an equation
- Replies:
**4** - Views:
**5358**

This is called an "arithmetic series". Each term in an arithmetic series ALWAYS has a difference of "d" between each term. Subtract any term in this sequence by the one that preceded it and the answer is always d=(I'll let you figure this one out). If you want to calculate the actual cost of 100 app...

- Fri Jan 11, 2013 12:08 am
- Forum: Intermediate Algebra
- Topic: Question on deriving the quadratic formula
- Replies:
**5** - Views:
**3250**

everything got divided through by "a" (step 4), which leaves the whole equation essentially unchanged. You just didn't notice, that's all. After step 5, which is not shown in your post, multiply the term "-c/a" by "4a/4a", which will give you "-4ac/4a 2 " Add the two terms on the right, square-root ...