- Wed Oct 12, 2016 11:07 pm
- Forum: Beginning Algebra
- Topic: floor tiles: 12" by 12"; how many needed for 12ft by 31ft floor?
- Replies:
**6** - Views:
**64**

So it is 12 x 31 which equal ls 372. No. It's 12 feet by 31 feet, which equals 372 square feet. The units make a huge difference! Since the tiles are 12 by 12 inches squared No. They're 12 inches by 12 inches, for 144 square inches; or 1 foot by 1 foot, for 1 square foot. The units are necessary to...

- Wed Oct 12, 2016 11:04 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)
- Replies:
**3** - Views:
**55**

Please help We'll be glad to -- once we know what the questions are. Please reply with the info I asked for. Also, I gave you links to lessons to help you learn the material, so you can get started on these yourself. Please now study those lessons and try each of the problems. Then please show us w...

- Wed Oct 12, 2016 2:55 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)
- Replies:
**3** - Views:
**55**

I need answers to these questions urgently please help. 1. Log3(x+1)-1=3+log(x-1) The instructions said something like "solve the equation", right? Is there some significance to the one log being capitalized as "Log" and the other not being? Is the "3" after the "...

- Mon Aug 22, 2016 8:58 pm
- Forum: Geometry
- Topic: circle problem
- Replies:
**1** - Views:
**309**

If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. Please help me. What have you tried? You drew the circles; labeled the chord's endpoints (say, A and B), the circles' centers (say, P and Q); drew the segments AB and PQ; and labe...

- Tue Aug 02, 2016 5:38 pm
- Forum: Arithmetic
- Topic: population of bacteria doubles in two hours
- Replies:
**2** - Views:
**616**

Hi, my son is going to six grades this year... "Generation time is the time it takes for a population of bacteria to double in number. If you begin with one X bacteria and one Y bacteria, what is the difference between the numbers of X bacteria and the number of Y bacteria produced in two hour...

- Wed Jun 01, 2016 9:03 pm
- Forum: Beginning Algebra
- Topic: Cancelling factors with multiplication problem
- Replies:
**1** - Views:
**375**

I'm having a little trouble understanding why I can't factor certain groups in this equation: Original eq.: x^2+2xy+y^2/x^2-2xy+y^2 multiplied by (x-y)/5x+5y What you've posted means this \left(x^2\, +\, 2xy\, +\, \dfrac{y^2}{x^2}\, -\, 2xy\, +\, y^2\right)\, \times\, \left(\dfrac{x\, -...

- Thu May 12, 2016 5:31 pm
- Forum: Calculus
- Topic: How would you solve x^2*e^x/x^2+e^x ? (* symbolizing multipication)
- Replies:
**2** - Views:
**660**

I got the answer x*e^x(x+2e^x)/2x+e^x , but the answer my textbook gives is x*e^x(x^3+2e^x)/(x^2+e^x)^2. I don't understand why there is an x^3 in the parenthesis nor why the bottom section is squared. What do you mean by "solving" the expression? (Only equations can be solved. Expression...

- Thu May 12, 2016 5:28 pm
- Forum: Beginning Algebra
- Topic: linear equations
- Replies:
**1** - Views:
**414**

Good morning, I am having trouble grasping the concept of how to setup linear equations. I could really use some help with the following problem: At a football game, dad purchases hot dogs for $1.25 and drinks for $1.75. If he purchases 9 items for $13.25, how many of each did he purchase? This is ...

- Fri Apr 08, 2016 1:25 pm
- Forum: Calculus
- Topic: Optimization problem is giving me ALOT of trouble.
- Replies:
**1** - Views:
**535**

2. A shed will have square ends and a sloped roof. Did they maybe have a picture with this? Because if two sides are square, then they can't have a sloped roof over them. The sides would have to have triangles of some kind above any squares. When you write back, please show what you did so far, lik...

- Sat Apr 02, 2016 12:07 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: solving for x given: 4e^-.2x + 3e^-.3x = 5
- Replies:
**4** - Views:
**481**

b-thanks and the 5 should be .5 So you meant this: \mbox{Solve }\, 4e^{-0.2x}\, +\, 3e^{-0.3x}\, =\, 0.5 Try using the steps, etc, explained in your other thread . The equations are pretty much the same so the methods will be pretty much the same too. If you get stuck, please write back showing wha...