- Wed Jun 01, 2016 9:03 pm
- Forum: Beginning Algebra
- Topic: Cancelling factors with multiplication problem
- Replies:
**1** - Views:
**95**

I'm having a little trouble understanding why I can't factor certain groups in this equation: Original eq.: x^2+2xy+y^2/x^2-2xy+y^2 multiplied by (x-y)/5x+5y What you've posted means this \left(x^2\, +\, 2xy\, +\, \dfrac{y^2}{x^2}\, -\, 2xy\, +\, y^2\right)\, \times\, \left(\dfrac{x\, -...

- Thu May 12, 2016 5:31 pm
- Forum: Calculus
- Topic: How would you solve x^2*e^x/x^2+e^x ? (* symbolizing multipication)
- Replies:
**1** - Views:
**33**

I got the answer x*e^x(x+2e^x)/2x+e^x , but the answer my textbook gives is x*e^x(x^3+2e^x)/(x^2+e^x)^2. I don't understand why there is an x^3 in the parenthesis nor why the bottom section is squared. What do you mean by "solving" the expression? (Only equations can be solved. Expression...

- Thu May 12, 2016 5:28 pm
- Forum: Beginning Algebra
- Topic: linear equations
- Replies:
**1** - Views:
**148**

Good morning, I am having trouble grasping the concept of how to setup linear equations. I could really use some help with the following problem: At a football game, dad purchases hot dogs for $1.25 and drinks for $1.75. If he purchases 9 items for $13.25, how many of each did he purchase? This is ...

- Fri Apr 08, 2016 1:25 pm
- Forum: Calculus
- Topic: Optimization problem is giving me ALOT of trouble.
- Replies:
**1** - Views:
**345**

2. A shed will have square ends and a sloped roof. Did they maybe have a picture with this? Because if two sides are square, then they can't have a sloped roof over them. The sides would have to have triangles of some kind above any squares. When you write back, please show what you did so far, lik...

- Sat Apr 02, 2016 12:07 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: solving for x given: 4e^-.2x + 3e^-.3x = 5
- Replies:
**4** - Views:
**186**

b-thanks and the 5 should be .5 So you meant this: \mbox{Solve }\, 4e^{-0.2x}\, +\, 3e^{-0.3x}\, =\, 0.5 Try using the steps, etc, explained in your other thread . The equations are pretty much the same so the methods will be pretty much the same too. If you get stuck, please write back showing wha...

- Sat Apr 02, 2016 12:05 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: solving for x, given exponentials: 4e^2x + 5e^3x = 15
- Replies:
**7** - Views:
**466**

I meant b So you meant this: \mbox{Solve }\, 4e^{2x}\, +\, 5e^{3x}\, =\, 15\, \mbox{ for the value of }\, x. and in order to solve say e^(2x) = Y I would take log of both sides so- Taking logs of both sides would give you this: \ln\left(\,4e^{2x}\, +\, 5e^{3x}\,\right) =\, \ln(15) Y...

- Fri Mar 18, 2016 3:15 pm
- Forum: Calculus
- Topic: u substitutions
- Replies:
**3** - Views:
**304**

wiloben25 wrote:i understand that u=t^2 gives rise to du = 2t dt however i can't wrap my head around how this integrates into the orginal through substituition.

Use the next step that I gave you. The numerator is t^5 dt = (t^2 t^2 t) dt = (t^2)^2 (t dt) = ... and so forth.

- Fri Mar 18, 2016 3:14 pm
- Forum: Arithmetic
- Topic: Calculating An Equation
- Replies:
**1** - Views:
**203**

For homework, I have been given four points and I want to figure out the equation for them. The points are: (1,4) (2,8) (3,16) (4,32) The point is that the equation doesn't match all of the given points. What is your equation? How did you get it? Please reply as soon as possible by this evening. Li...

- Thu Mar 17, 2016 3:47 pm
- Forum: Calculus
- Topic: u substitutions
- Replies:
**3** - Views:
**304**

wiloben25 wrote:stuck on this

use a substitution u=t^2 to solve the integration t^5/sqrt(3-t^4)

They gave you u = t^2, so you know du = 2t dt and u^2 = t^4. Plugging in with this gives t^5 dt = u^2 du, etc. Where are you stuck? Please show all of your work so far. Thanks.

- Thu Mar 17, 2016 3:45 pm
- Forum: Arithmetic
- Topic: What is inverse property of addition?
- Replies:
**3** - Views:
**454**

Smrithi wrote:What is inverse property of addition?

Pls explain with few examples

There's loads of examples online. Where are you stuck with this?