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by theshadow
Fri Apr 01, 2016 3:09 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: solving for x, given exponentials: 4e^2x + 5e^3x = 15
Replies: 7
Views: 230

Re: solving for x, given exponentials: 4e^2x + 5e^3x = 15

denicarl wrote:if I have 4e^2x + 5e^3x = 15
how do I solve for x?

What you wrote means this:

a.

Is that right? Or did you mean this?

b.

denicarl wrote:I tried ln 4 +2x+ln5+3x=ln 15 but that doesn't work.

How did you get to this step?

Thanks.
by theshadow
Fri Apr 01, 2016 3:08 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: solving for x given: 4e^-.2x + 3e^-.3x = 5
Replies: 4
Views: 81

Re: solving for x given: 4e^-.2x + 3e^-.3x = 5

denicarl wrote:how do I solve for x given: 4e^-.2x + 3e^-.3x = 5

The way you've written it means this:

a.

Did you mean this?

b.

Thanks.
by theshadow
Tue Mar 29, 2016 1:03 pm
Forum: Intermediate Algebra
Topic: Question about polynomials.
Replies: 1
Views: 178

Re: Question about polynomials.

squirrel wrote:Hi all,

I have a quick question regarding polynomials. Can I use long division or synthetic division, or both? Thanks in advance. :wave:

Depends on the context, but "both" is probably fine in most cases.
by theshadow
Sat Jan 23, 2016 1:12 pm
Forum: Beginning Algebra
Topic: LCD inquiry
Replies: 3
Views: 519

Re: LCD inquiry

magellan333 wrote:The instructions were to find the LCD of the three. I factored as follows:

X-7 = x-7
3x-21 = 3(x-7)
6x=6x

Therefore my answer was x-7, 3 and 6x.

Okay. Now, after you've read the lesson in the link and factored the 6 in the 6x, what are you getting?
by theshadow
Wed Jan 20, 2016 11:35 pm
Forum: Beginning Algebra
Topic: LCD inquiry
Replies: 3
Views: 519

Re: LCD inquiry

X-7, 3x-21, 6x My answer was 3, x-7, 6x "Your answer" to what? What did the instructions tell you to do? Correct answer per the book is 6x, x-7. If the instructions said to get the factors for the LCD then this answer is right. You can see why here (the last bit of the lesson shows polys;...
by theshadow
Sat Jan 16, 2016 1:01 am
Forum: Beginning Algebra
Topic: How do I know the order (simple I know!)
Replies: 1
Views: 435

Re: How do I know the order (simple I know!)

I have to subtract one equation from another to get my answer. I have to subtract S=0.1M + 18660 from S=5M - 174200. How and why do I know to do S=(5M - 0.1M) - (174200 +18660)? I mean why would I not do '0.1M - 5M'? They said to take 0.1M + 18,600 FROM 5M - 174,200. You're saying you want to do it...
by theshadow
Sun Dec 27, 2015 1:49 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: F of X g of x
Replies: 1
Views: 751

Re: F of X g of x

I've been racking my brain trying to...figure out the mathematics essentially given an equation for f(x) such as 2x+1 and f (3)=g (1) solve for g (x) how would I go about doing this mathematically You say "essentially". What is the question "exactly" (and the instructions)? Than...
by theshadow
Tue Dec 22, 2015 9:16 pm
Forum: Beginning Algebra
Topic: Please show steps of factoring: X + (X*.06) = 273.45, X = ?
Replies: 1
Views: 569

Re: Please show steps of factoring: X + (X*.06) = 273.45, X = ?

X + (X*.06) = 273.45 X = ? The 2nd term (X*.06) means (X) * (0.06) or 0.06 * X. The 1st term X means (X) * (1) or 1 * X. If you write it like: 1*X + 0.06*X = 273.45 Now factor out the X , simplify what's in the parens, divide off, and simplify to get the answer. If you get stuck, plz write back sho...
by theshadow
Sat Nov 21, 2015 11:38 pm
Forum: Trigonometry
Topic: Solve equation for a roof loading: =[2 x (3/2)Cos(45) x 1] x 2.25
Replies: 3
Views: 846

Re: Solve equation for a roof loading: =[2 x (3/2)Cos(45) x 1] x 2.25

I have an equation for a roof loading: =[2 x (3/2)Cos(45) x 1] x 2.25 What is the rest of the eqn? Whats on the left side4 of the "="? which is: 4.24x2.25 = 9.54 Is this maybe just an expression or what you got out of a formula? anyway, the only way to get 4.24 out of the bracketed part i...
by theshadow
Thu Nov 12, 2015 7:52 pm
Forum: Trigonometry
Topic: Finding all the solutions of the equation
Replies: 4
Views: 590

Re: Finding all the solutions of the equation

daz1990 wrote:Find all the solutions to the following equation

2Sin2(2x) + 4Sin(2x) = 4.003
where 0o < x < 360o

If they gave you 2x^2 + 4x = 4.003, what would you do? Do the same thing here. Then use your calc to get the solns to the trig eqns.

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