Search found 197 matches

Sun Nov 27, 2016 5:28 pm
Forum: Intermediate Algebra
Topic: fractional exponents help: how (5y^3/4)(2y^1/3) equals 10y^13/10
Replies: 1
Views: 942

Re: fractional exponents help: how (5y^3/4)(2y^1/3) equals 10y^13/10

Intermediate algebra was the correct spot right? If that's the class you're in, then yes. I don't understand how (5y^3/4)(2y^1/3) equals 10y^13/10 I have the answer but I don't understand how its reached. well at least not that 13/10 part The way you've posted means this: \left(\dfrac{5y^3}{4}\righ...
Sat Oct 22, 2016 7:06 pm
Forum: Matrix (Linear) Algebra
Topic: Word Problem confusion
Replies: 1
Views: 1664

Re: Word Problem confusion

I just need to ensure I have the equation correct. A, B, and C build houses. Each house can be build in the following ways: i) A and B work together for 6 hours, and C works for 4 hours ii) A and B work together for 2 hours, and C works for 8 hours iii) A works alone for 3 hours, B works alone for ...
Wed Oct 19, 2016 2:54 pm
Forum: Matrix (Linear) Algebra
Topic: Find >= 3 different elt's, adding, scalar-multiplying: [x,y]', x,y>=0
Replies: 1
Views: 394

Re: Find >= 3 different elt's, adding, scalar-multiplying: [x,y]', x,y>=0

I am very confused on how to begin this problem. The image is blurry. I think it says this: Given: . . . V\, =\, \left\{\, [x,\, y]'\, \in\, \mathbb{R}^2\, :\, x\, \geq\, 0\, \mbox{ and }\, y\, \geq\, 0\, \right\} Present at least three different elements of the set V . After adding and scalar-mult...
Wed Oct 12, 2016 11:44 pm
Forum: Intermediate Algebra
Topic: Gaussian Elimination: x+y+z=5, 2x+3y+5z=8, 4x+5z=2
Replies: 1
Views: 721

Re: Gaussian Elimination: x+y+z=5, 2x+3y+5z=8, 4x+5z=2

there are arrows connecting the rows of numbers together. what's that all about? The arrows (which we can't see) are probably what they show here . Please help me. I have no idea how to solve this problem. How do I even start? Solve by Gaussian Elimination: x+y+z=5 2x+3y+5z=8 4x+5z+2 They were supp...
Sun Jul 31, 2016 1:09 pm
Forum: Beginning Algebra
Topic: Larger numbers taking from smaller ones
Replies: 1
Views: 986

Re: Larger numbers taking from smaller ones

What are the precise rules for the "interactions"?
Thu Jun 16, 2016 1:33 pm
Forum: Uncategorized
Topic: Math learning software?
Replies: 3
Views: 1187

Re: Math learning software?

I think the MathHelp.com stuff is supposed to be pretty good. Purplemath endorses it.
Mon Apr 18, 2016 4:44 pm
Forum: Discrete Math
Topic: Lone chooser problem
Replies: 1
Views: 1341

Re: Lone chooser problem

Al, Betty, and Carl divide a pizza, which they agree is worth \$12. They get a half-cheese and half-mushroom pizza. They will use the Lone Chooser Method and Betty becomes the chooser leaving Al and Carl as the dividers. I'll be using the "Lone Chooser Method" they show in this PDF : i) one is rando...
Sun Apr 17, 2016 12:00 pm
Forum: Beginning Algebra
Topic: Need help on solving Linear Algebra And Its Application Problem Set 1.2 Problem 2
Replies: 1
Views: 908

Re: Need help on solving Linear Algebra And Its Application Problem Set 1.2 Problem 2

"Sketch these three lines and decide if the equations are solvable: x\,+\,2y\,=\,2 x\, -\, y\,=\,2 y\,=\,1 What happens if all right-hand sides are zero? Is there any nonzero choice of right-hand sides that allows the three lines to intersect at the same point?" I am having a hard time solving the ...
Thu Apr 07, 2016 10:52 am
Forum: Beginning Algebra
Topic: factorization and grouping: 6t^7x^9 - 8x^4t^9 = 0
Replies: 2
Views: 930

Re: simplifying equations

6t^7x^9 - 8x^4t^9 = 0 i have to simplify the above equation "simplify" or "solve"? can anyone please explain the method so that i can put it into action? simple factoring: http://www.purplemath.com/modules/simpfact.htm special factoring: http://www.purplemath.com/modules/specfact.htm Then use the z...
Mon Jan 25, 2016 8:21 pm
Forum: Intermediate Algebra
Topic: inverse proportion
Replies: 1
Views: 1559

Re: inverse proportion

Please help! I am having a trouble understanding what steps to take to get the answer. They show the steps here . Suppose that y is inversely proportional to x and that y-7/8 when x=16. Is the "y-7/8" supposed to be "y = 7/8", "y = -7/8", or something else? I understand I have to multiply both side...